2[t-(2t+8)+6]=2(t+2)

Solution for 2[t-(2t+8)+6]=2(t+2) equation:

Simplifying
2[t + -1(2t + 8) + 6] = 2(t + 2)

Reorder the terms:
2[t + -1(8 + 2t) + 6] = 2(t + 2)
2[t + (8 * -1 + 2t * -1) + 6] = 2(t + 2)
2[t + (-8 + -2t) + 6] = 2(t + 2)

Reorder the terms:
2[-8 + 6 + t + -2t] = 2(t + 2)

Combine like terms: -8 + 6 = -2
2[-2 + t + -2t] = 2(t + 2)

Combine like terms: t + -2t = -1t
2[-2 + -1t] = 2(t + 2)
[-2 * 2 + -1t * 2] = 2(t + 2)
[-4 + -2t] = 2(t + 2)

Reorder the terms:
-4 + -2t = 2(2 + t)
-4 + -2t = (2 * 2 + t * 2)
-4 + -2t = (4 + 2t)

Solving
-4 + -2t = 4 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-4 + -2t + -2t = 4 + 2t + -2t

Combine like terms: -2t + -2t = -4t
-4 + -4t = 4 + 2t + -2t

Combine like terms: 2t + -2t = 0
-4 + -4t = 4 + 0
-4 + -4t = 4

Add '4' to each side of the equation.
-4 + 4 + -4t = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -4t = 4 + 4
-4t = 4 + 4

Combine like terms: 4 + 4 = 8
-4t = 8

Divide each side by '-4'.
t = -2

Simplifying
t = -2